Question

tìm x

a\(\dfrac{5x-3}{3-2x}=\dfrac{2}{3}\)

b\(\left(\dfrac{4}{5}x+\dfrac{2}{3}\right)\div\dfrac{3}{4}=2\)

c\(\dfrac{3}{4}x-\dfrac{1}{3}=\dfrac{3}{5}\)

d\(\dfrac{2}{3}-\dfrac{3}{5}\div x=\dfrac{1}{4}\)

giúp mình nhé

Answer 1

Answer 2

a) \(\dfrac{5x-3}{3-2x}=\dfrac{2}{3}\)

\(\Rightarrow3\left(5x-3\right)=2\left(3-2x\right)\)

\(\Rightarrow15x-9=6-4x\)

\(\Rightarrow15x+4x=9+6\)

\(\Rightarrow19x=15\Rightarrow x=\dfrac{15}{19}\)

b) \(\left(\dfrac{4}{5}x+\dfrac{2}{3}\right):\dfrac{3}{4}=2\)

\(\Rightarrow\dfrac{4}{5}x+\dfrac{2}{3}=\dfrac{3}{2}\Rightarrow\dfrac{4}{5}x=\dfrac{5}{6}\)

\(\Rightarrow x=\dfrac{25}{24}\)

c) \(\dfrac{3}{4}x-\dfrac{1}{3}=\dfrac{3}{5}\Rightarrow\dfrac{3}{4}x=\dfrac{14}{15}\)

\(\Rightarrow x=\dfrac{56}{45}\)

d) \(\dfrac{2}{3}-\dfrac{3}{5}:x=\dfrac{1}{4}\Rightarrow\dfrac{3}{5}:x=\dfrac{5}{12}\)

\(\Rightarrow x=\dfrac{36}{25}\)

Answer 3