Question

tìm x

a)(5x-1)^2-5x(5x-1)=0

b)x(x+1)(x+2)=0

c)(3x+2)x-3(3x+2)=0

Answer 1

a/ \(\left(5x-1\right)^2-5x\left(5x-1\right)=0\)

\(\Leftrightarrow\left(5x-1\right)\left(5x-1-5x\right)=0\Leftrightarrow1-5x=0\Leftrightarrow x=\dfrac{1}{5}\)

Vaayj........

b/ \(x\left(x+1\right)\left(x+2\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x+1=0\Leftrightarrow x=-1\\x+2=0\Leftrightarrow x=-2\end{matrix}\right.\)

Vay......

c/ \(\left(3x+2\right)x-3\left(3x+2\right)=0\)

\(\Leftrightarrow\left(3x+2\right)\left(x-3\right)=0\Leftrightarrow\left[{}\begin{matrix}3x+2=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{2}{3}\\x=3\end{matrix}\right.\)

Vậy.....