Question

Tìm x:

a) \(\dfrac{x}{-9}=\dfrac{-40}{45}\)

b) \(\left|2x+\dfrac{1}{3}\right|+\dfrac{4}{9}=-5+\sqrt{\dfrac{16}{81}}\)

Answer 1

a) \(\dfrac{x}{-9}=\dfrac{-40}{45}\)

\(\Leftrightarrow x.45=\left(-9\right).\left(-40\right)\)

\(\Leftrightarrow x.45=360\)

\(\Leftrightarrow x=\dfrac{360}{45}=8\)

Vậy x=8

Answer 2

b: \(\Leftrightarrow\left|2x+\dfrac{1}{3}\right|+\dfrac{4}{9}=-5+\dfrac{4}{9}\)

=>|2x+1/3|=-5(vô lý)

a: \(\Leftrightarrow x=\dfrac{-40\cdot\left(-9\right)}{45}=8\)