Question

Tìm x:

a) \(\dfrac{16}{3}:x=\dfrac{50}{12}\left(-0,06\right)\) b) \(2.x-1^3=-8\) c) \(\dfrac{\left(0.8\right)^5}{\left(0.4\right)^6}=x\)

d)\(0,944-2.x=3,268\) e)\(\sqrt{\dfrac{0,09}{25}=-\dfrac{4,7}{5}+x}\) g)\(\sqrt{5^2-3^2}=-\sqrt{81-x}\)

Answer 1

a) x = \(\dfrac{-64}{3}\)

b) x = -3,5

c) x = 80

d) x = -1.162

e) x = 0,9436

g) x \(\in\varnothing\)

Answer 2

a) 16/3 : x = -1/4

=> x = 16/3 : (-1/4)

=> x = 16/3 . (-4)

=> x = -64/3

Vậy x= -64/3

b)2x - 1³ = -8

=> 2x = (-8) + 1

=> 2x = -7

=> x = -7/2

d) 0,944 - 2x = 3,268

=> 2x = 0,944 - 3,268

=> 2x = -2,324

=> x = (-2,324) : 2

=> x = -1,162

g) \(\sqrt{5^2-3^2}=-\sqrt{81-x}\)

=> \(\sqrt{25-9}\)= \(-\sqrt{81-x}\)

=> \(\sqrt{16}\)=\(-\sqrt{81-x}\)

=> 4=\(-\sqrt{81-x}\)

tới đây mik bí r hk bt lm nữa