Question

Tìm x

3x + \(\dfrac{1}{8}\)=\(2\dfrac{3}{4}\)

(4,5 - 200 %. x).\(1\dfrac{4}{7}=\dfrac{11}{14}\)

Giúp mk vs ạ

Answer 1

Anh làm lại câu b)

\(\left(4,5-200\%x\right).1\dfrac{4}{7}=\dfrac{11}{14}\\ < =>\left(\dfrac{9}{2}-2x\right).\dfrac{11}{7}=\dfrac{11}{14}\\ =>\dfrac{9}{2}-2x=\dfrac{\dfrac{11}{14}}{\dfrac{11}{7}}=\dfrac{1}{2}\\ =>2x=\dfrac{9}{2}-\dfrac{1}{2}=4\\ =>x=\dfrac{4}{2}=2\)

Answer 2

a, \(3x+\dfrac{1}{8}=2\dfrac{3}{4}\\ < =>3x+\dfrac{1}{8}=\dfrac{11}{4}\\ =>3x=\dfrac{11}{4}-\dfrac{1}{8}=\dfrac{21}{8}\\ =>x=\dfrac{\dfrac{21}{8}}{3}=\dfrac{7}{8}\)

b, \(\left(4,5-200\%x\right).1\dfrac{4}{7}=\dfrac{11}{14}\\ < =>\left(4,5-2x\right).\dfrac{11}{7}=\dfrac{11}{4}\\ =>4,5-2x=\dfrac{11}{4}:\dfrac{11}{7}=\dfrac{7}{4}\\ =>2x=4,5-\dfrac{7}{4}=\dfrac{11}{4}\\ =>x=\dfrac{\dfrac{11}{4}}{2}=\dfrac{11}{8}\)

Answer 3

a) 3x + \(\dfrac{1}{8}\) = \(2\dfrac{3}{4}\)

3x + \(\dfrac{1}{8}=\dfrac{11}{4}\)

3x \(=\dfrac{11}{4}-\dfrac{1}{8}=\dfrac{21}{8}\)

x \(=\dfrac{21}{8}:3=\dfrac{7}{8}\)

Vậy x = \(\dfrac{7}{8}\).

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(4,5 - \(2\)x) . \(\dfrac{11}{7}\) = \(\dfrac{11}{14}\)

(4,5 - 2x) \(=\dfrac{11}{14}:\dfrac{11}{7}=\dfrac{1}{2}\)

2x \(=4,5-\dfrac{1}{2}=4\)

x \(=4:2=2\)

Vậy x = 2.

Answer 4

a) \(3x+\dfrac{1}{8}=2\dfrac{3}{4}\)

\(\Rightarrow3x+\dfrac{1}{8}=\dfrac{11}{4}\)

\(\Rightarrow3x=\dfrac{11}{4}-\dfrac{1}{8}\)

\(\Rightarrow3x=\dfrac{22}{8}-\dfrac{1}{8}\)

\(\Rightarrow3x=\dfrac{21}{8}\)

\(\Rightarrow x=\dfrac{21}{8}:3\)

\(\Rightarrow x=\dfrac{21}{8}\cdot\dfrac{1}{3}\)

\(\Rightarrow x=\dfrac{7}{8}\)

Vậy \(x=\dfrac{7}{8}\).

b) \(\left(4.5-200\%x\right)\cdot1\dfrac{4}{7}=\dfrac{11}{14}\)

\(\Rightarrow\left(\dfrac{9}{2}-2x\right)\cdot\dfrac{11}{7}=\dfrac{11}{14}\)

\(\Rightarrow\dfrac{9}{2}-2x=\dfrac{11}{14}:\dfrac{11}{7}\)

\(\Rightarrow\dfrac{9}{2}-2x=\dfrac{11}{14}\cdot\dfrac{7}{11}\)

\(\Rightarrow\dfrac{9}{2}-2x=\dfrac{1}{2}\)

\(\Rightarrow2x=\dfrac{9}{2}-\dfrac{1}{2}\)

\(\Rightarrow2x=4\)

\(\Rightarrow x=\dfrac{4}{2}=2\)

Vậy \(x=2\).