Question

tìm x:

(3x-4).(x-1)^3=0

Answer 1

TH1 3x-4=0

suy ra 3x=4

suy ra x= 4/3

TH2 ( x-1 )^3 =0

suy ra x-1=0

suy ra x=1

Vậy x=4/3;x=1

Answer 2

\(\left(3x-4\right).\left(x-1\right)^3=0\)

\(\left(3x-4\right).\left(x-1\right)=0\)

=> \(3x-4=0\) hay \(x-1=0\)

\(3x=0+4\) hay \(x=0+1\)

\(3x=4\) hay \(x=1\)

\(x=4:3\) hay x = 1

=> \(x=\dfrac{4}{3}\) hay x = 1