(2x + 1)3 = 125
=> (2x + 1)3 = 53
=> 2x + 1 = 5
=> 2x = 5 - 1
=> 2x = 4
=> x = 4 : 2
=> x = 2
Vậy x = 2
( 2x + 1 )3 = 125
( 2x + 1 )3 = 53
=> 2x + 1 = 5
2x = 5 - 1
2x = 4
x = 4 : 2
x = 2
\(\left(2x+1\right)^3=125\)
\(\Rightarrow\left(2x+1\right)^3=5^3\)
\(\Rightarrow2x+1=5\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2\)
( 2x + 1 )\(^3\)= 125
( 2x + 1 )\(^3\) = 5\(^3\)
\(\Rightarrow\) 2x + 1 = 5
2x = 5 - 1
2x = 4
x = 4 : 2 = 2
Vậy x = 2
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