Question

Tìm x: 2x . \(\left(x-\dfrac{1}{7}\right)\)= 0

Answer 1

\(2x.\left(x-\dfrac{1}{7}\right)=0\)
\(=>\left[{}\begin{matrix}2x=0\\x-\dfrac{1}{7}=0\end{matrix}\right.\)
\(=>\left[{}\begin{matrix}x=0 \\\dfrac{1}{7}\end{matrix}\right.\)
Vậy \(x=0\) hoặc \(x=\dfrac{1}{7}\)

Answer 2

\(2x\cdot\left(x-\dfrac{1}{7}\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}2x=0\\x-\dfrac{1}{7}=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{7}\end{matrix}\right.\)

Vậy x=0 hoặc \(\dfrac{1}{7}\)

Answer 3

\(\Rightarrow\left[{}\begin{matrix}2x=0\\x-\dfrac{1}{7}=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=0:2\\x=0+\dfrac{1}{7}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{7}\end{matrix}\right.\)

Vậy x = 0 hoặc x = \(\dfrac{1}{7}\)

Answer 4

\(2x\left(x-\dfrac{1}{7}\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}2x=0\\x-\dfrac{1}{7}=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{7}\end{matrix}\right.\)