Ta có: \(\left(2x-5\right)\cdot3=\left(3-x\right)\cdot4\)
\(\Leftrightarrow6x-15=12-4x\)
\(\Leftrightarrow6x+4x=12+15\)
\(\Leftrightarrow10x=27\)
hay \(x=\dfrac{27}{10}\)
Vậy: \(x=\dfrac{27}{10}\)
tìm x, biết
1. -11/2x + 1= 1/3x - 1/4
2. 2x- 2/3 - 7x = 3/2 - 1
3. 3/2x - 2/5 = 1/3x - 1/4
4. 2/3 - 5/3x= 7/10x + 5/6
5. 2x -1/4 = 5/6 - 1/2x
6. 3x - 5/3 = x - 1/4
7. - 5/6 + 3x = 2/3 - 1/2x
8. 1/2 ( x + 2 ) - 4( x - 1/4 ) = 1/2x
9. 5/2( x - 3/5 ) - 1/10 = x-3
10. -4/3( x - 1/4 ) = 3/2( 2x - 1 )
Giúp mk với !!!
1) 2x + x (x - 5) = 3x^2 -x
2) 15 - 5 ( 1 - 2x) = 12 - x
3) 2/3 - 1/3 ( x-3/2 ) - 1/2 ( 2x +1) =5
4) | x - 4/5 | = 3/5
1) | x+4\5 | + 7\5 = 3\5
2) | x + 2 |= x-3
3) 5- | x - 2\3| - 2= x
4) |x- 4 | = | 2x+3 |
5) (x - 1\3 )^3 = -1\27
6) (x + 1\2)^2 = 5\5
7) | (- 2\2\3)^2 - x | - 1\3 = 0
Tìm \(x\in Q\), biết rằng :
a) \(\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\)
b) \(2x\left(x-\dfrac{1}{7}\right)=0\)
c) \(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
Tìm x ạ
b) \(\left|\dfrac{3}{4}x-\dfrac{3}{4}\right|-\dfrac{3}{4}=\left|\dfrac{-3}{4}\right|\)
c) \(\left|x+\dfrac{3}{5}\right|-\left|x-\dfrac{7}{3}\right|=0\)
1) Thực hiện phép tính:
a) (-3+4):2 b) -4+(-5)-17 c) 4-[(-11)-(2+5)]
5 9 7 9 9 4 3 6 9 3
2) Tìm x biết:
a) 2+7:x=5 b) (-0,75 x +5).4-(-1)=-5 c)-x+5=1,2 d)2+2x=1
3 4 6 2 7 3 6 3 3 2
3) Tìm số nguyên x,y biết:
x-1=1
4 y 2
Tìm x :
\(7-\dfrac{1}{2}.\left(2x-5\right)-\dfrac{2}{3}\left(3x+1\right)=5\)
bài 1: Tìm x biết:
a,\(x+\dfrac{1}{4}=\dfrac{3}{4}\)
b,\(\dfrac{3}{4}-\dfrac{2}{5}x=\dfrac{29}{60}\)
c,\(2x-\dfrac{1}{3}=\dfrac{-5}{6}\)
d,\(2-x:\dfrac{3}{4}=\dfrac{1}{2}\)
e,\(\dfrac{11}{12}-\dfrac{2}{3}|x|=\dfrac{3}{8}\)
f,\(|2x-1|=5\)
lưu ý: Có câu có 2 trường hợp
Các bn giúp mk với
1) Tìm x:
a) \(\frac{11}{12}-\frac{5}{12}.\left(\frac{2}{5}+x\right)=\frac{2}{3}\)
b) \(\frac{3}{4}+\frac{1}{4}:x=\frac{2}{5}\)
c) 2x.(x-\(\frac{1}{7}\))=0
d) (x + 1) . (x - 2) < 0
e) (x - 2) . ( x + \(\frac{2}{3}\) ) >0
