\(\dfrac{1}{x}+1=\dfrac{13}{25}\)
\(\dfrac{1}{x}=\dfrac{13}{25}-1\)
\(\dfrac{1}{x}=\dfrac{-12}{25}\)
\(\Rightarrow-12.x=1.25\)
\(-12.x=25\)
\(x=25:\left(-12\right)\)
\(x=\dfrac{-25}{12}\)
\(\dfrac{1}{x+1}\)=\(\dfrac{13}{25}\) => 1.25=13.(x+1)
25 = 13x +13
13x = 25-13
13x = 12
x = \(\dfrac{12}{13}\)
\(\dfrac{1}{x}+1=\dfrac{13}{25}\)
\(\dfrac{1}{x}=\dfrac{13}{25}-1\)
\(\dfrac{1}{x}=\dfrac{13}{25}-\dfrac{25}{25}\)
\(\dfrac{1}{x}=\dfrac{-12}{25}\)
\(x=\dfrac{1\cdot25}{-12}\)
\(x=\dfrac{-25}{12}\)
Vậy \(x=\dfrac{-25}{12}\).
Trần Thị Khánh Huyền ơi, đề bài là \(\dfrac{1}{x}\)+ 1 = \(\dfrac{13}{25}\) hay là \(\dfrac{1}{x+1}\)=\(\dfrac{13}{25}\)z???
\(\dfrac{1}{x+1}=\dfrac{13}{25}\)
\(x+1=\dfrac{1\cdot25}{13}\)
\(x+1=\dfrac{25}{13}\)
\(x=\dfrac{25}{13}-1\)
\(x=\dfrac{12}{13}\)
Vậy \(x=\dfrac{12}{13}\).
