Question

Tìm x

\(190-\left(x-1\right)^2=189\)

\(5^{x+1}-4.5^x-10=15\)

Help me !!!!!!!!!!!!!

Answer 1

 

Tìm x

190−(x−1)2=189

(x - 1) ² = 190 - 189

(x - 1) ² = 1

x = 1+2

x = 2

 

 

 

 

Answer 2

a, cái câu trả lời trước mk ghi sai

190 - (x-1)² = 189

(x - 1 ) ² = 190 - 189

(x-1)² = 1

x = 1+1

x = 2

Answer 3

a) \(190-\left(x-1\right)^2=189\)

=> \(\left(x-1\right)^2=190-189=1\)

\(\Rightarrow x-1\in\left\{-1;1\right\}\Rightarrow x\in\left\{0;2\right\}\)

Vậy \(x\in\left\{0;2\right\}\)

b) \(5^{x+1}-4.5^x-10=15\)

\(\Rightarrow5^x.5-4.5^x=15+10=25\)

\(\Rightarrow5^x.\left(5-4\right)=25\Rightarrow5^x=25\)

\(\Rightarrow x=2\)

Vậy x = 2

Answer 4

\(190-\left(x-1\right)^2=189\)

\(\left(x-1\right)^2=190-180\)

\(\left(x-1\right)^2=1\)

\(\left(x-1\right)^2=1^2\)

\(x-1=1\)

\(x=0\)

 

Answer 5

Dễ ợt luôn bạn.

Answer 6

Mai mk nộp r`

Answer 7

Nguyễn Huy Thắng

Nguyễn Huy Tú

Trương Hồng Hạnh

soyeon_Tiểubàng giải

MK NGU TOÁN lắm

Answer 8

ai giúp đc thì giúp vs

Answer 9

190 - ( x - 1 ) ^ 2 = 189

( x - 1 ) ^ 2 = 190 - 189

( x - 1 ) ^ 2 =1

( x - 1 ) ^ 2 = 1 ^2

x - 1 = 1

x = 1 + 1

x = 2

5 ^ x + 1 - 4 . 5 ^ x - 10 = 15