d) (5x+3) ( 4x-1) +(10x-7) (-2x+3) =27
e)(8x-5) (3x+2) -(12x+7) (2x-1)=17
f) (5x+9) (6x-1) -(2x-3)( 15z+1) = -190
g) 6x(5x+3) + 3x(1-10x) =7
h) (3x-3) (5 -21x) +(7x+4)(9x-5) =44\
i) (x+1)(x+2)(x-5)-x2 (x+8)=27
Tìm x, biết:
(4x-1)2-(3x+2)(3x-2)= (7x-1)(x+2)+(2x+1)2-(4x2+7)
(5x-1)(x+1)-2(x-3)2= (x+2)(3x-1)-(x+4)2+(x2-x)
(-x+5)(x-2)+(x-7)(x+7)= (3x+1)2-(3x-2)(3x+2)
(2x+3)2-(5x-4)(5x+4)= (x+5)2-(3x-1)(7x+2)-(x2-1)
(1-3x)2-(x-2)(9x+1)= (3x-4)(3x+4)-9(x+3)2
Phân tích các đa thức sau thành nhân tử :
1) x3- 7x + 6
2) x3 - 9x2 + 6x + 16
3) x3 - 6x2 - x + 30
4) 2x3 - x2 + 5x +3
5) 27x3 - 27x2 + 18x - 4
6) x2 + 2xy + y2 - x - y - 12
7) ( x + 2 )( x + 3 )( x + 4 )( x + 5 ) - 24
8) 4x4 - 32x2 + 1
9) 3( x4 + x2 + 1 ) - ( x2 + x + 1 )2
10) 64x4 + y4
11) a6 + a4 +a2b2 + b4 - b6
12) x3 + 3xy + y2 - 1
13) 4x4 + 4x3 + 5x2 + 2x + 1
14) x8 + x + 1
15) x8 + 3x4 + 4
16) 3x2 + 22xy + 11x + 37y + 7y2 + 10
17) x4 - 8x + 63
1. 6x(x - 10) - 2x+20=0 6. 3x2 - 6x+3=0
2. 3x2(x - 3) + 3(3 - x)=0 7. 4x2 - 10x+2=0
3. x2 - 8x+16=2(x -4) 8. x2 - 12x -18=0
4. x2 - 16 + 7x ( x+4)=0 9. 3x2 - 10x+3=0
5. x2 - 13x - 14=0 10. 5x2 - 10x+10=0
Bài 3: Giải các phương trình sau bằng cách đưa về dạng ax+b =0 :
a) \(\frac{3x-11}{11}-\frac{x}{3}=\frac{3x-5}{7}-\frac{5x-3}{9}\)
b) \(\frac{9x-0,7}{4}-\frac{5x-1,5}{7}=\frac{7x-1,1}{6}-\frac{5\left(0,4-2x\right)}{5}\)
c) \(\frac{5\left(x-1\right)+2}{6}-\frac{7x-1}{4}=\frac{2\left(2x-1\right)}{7}-5\)
d) \(14\frac{1}{2}-\frac{2\left(x+3\right)}{5}=\frac{3x}{2}-\frac{2\left(x-7\right)}{3}\)
Câu 1 : Giải phương trình
a. 5(x-3)-4=2(x-1)
b. 5-(6-x)=4(3-2x)
c. (3x+5)(2x+1)=(6x-2)(x-3)
d. (x+2)2 + 2(x-4)=(x-4)(x-2)
Bài 2 : Giải phương trình
a) x/3 - 5x/6 - 15x/12 = x/4 - 5
b) 8x-3/4 - 3x-2/2 = 2x-1/2 + x+3/4
c) x-1/2 - x+1/15 - 2x-13/6 = 0
d) 3(3-x)/8 + 2(5-x)/3 = 1-x/2 - 2
e) 3(5x-2)/4 - 2 = 7x/3 - 5(x-7)
Bài 3 Giải phương trình
a) (5x-4)(4x+6)=0
b) (x-5)(3-2x)(3x+4)=0
c) (2x+1)(x2+2)=0
d) (8x-4)(x2+2x+2)=0
Bài 4 Giải phương trình
a) (x-2)(2x+3)=(x-1)(x-2)
b) (2x+5)(x-4)=(x-5)(4-x)
c) 9x2 -1 =(3x+1)(2x-3)
d) (x+2)2=9(x2-4x+4)
e)4(2x+7)2 -9(x+3)2 =0
Bài 5 Giải phương trình
a) (9x2 -4)(x+1)=(3x+2)(x2 -1)
b) (x-1)2 -1+x2 =(1-x)(x+3)
c) x4 +x3 3+x+1=0
Câu 1. Giải các phườn trình sau:
a, 3x+6=0
b, 2x-10=0
c, 3x-7=11
d, 3x-9=0
e, 3x(2-x) =15(x-2)
f, (x+5)(x+4)=0
g, x(x+4)=0
h, (2x -4)(x-2)=0
i, (x+1/5)(2x-3)=0
k, x²-4x=0
m, 4x²-1=0
n, x²-6x+9=0
l, (3x-5)²-(x+4)²=0
o, 7x(x+2)-5(x+2)=0
p, 3x(2x-5)-4x+10=0
q, (2-2x)-x²+1=0
r, x(1-3x)=5(1-3x)
s, 2x-3/4+x+1/6=3
t, x-3/4-2x+1/3=x/6
u, x+1/13+x+2/12=x+3/11+x+4/10
v, 2x+1/15+2x+2/14=2x+3/13+2x+4/12
Giúp e nha mn. E cảm ơn trc ạ!
1. (4x-10).(24+5x)=0
2 .(2x-5).(3x-2)=0
3. (2x-1).(3x+1)=0
4. x.(\(x\)2-1)=0
5.(5x+3).(\(x^2\)+4).(x-1)=0
6.(x-1).(x+2).(x+3)=0
7.(x-1).(x+5).(-3x+8)=0
Giải phương trình:
1) (x - 5)2 + (x + 3)2 = 2(x - 4)(x + 4) - 5x + 7
2) (x + 3)(x - 2) - 2(x + 1)2 = (x - 3)2 - 2x2 + 4x
3) (x + 1)3 - (x + 2)(x - 4) = (x - 2)(x2 + 2x + 4) + 2x2
4) (x - 2)3 + (x - 5)(x + 5) = x(x2 - 5x) - 7x + 3
5) (x + 4)(x2 - 4x + 16) - x(x - 4)2 = 8(x - 3)(x + 3)
6) 4(x - 1)(x + 2) - 5(x + 7) = (2x + 3)2 - 5x + 3
7) (x - 1)(x2 + x + 1) + 3(x - 2)2 = x(x2 + 3x - 1)
8) (x + 5)(x - 5) - (x + 3)(x2 - 3x + 9) = 5 - x(x2 - x -2)
9) (x + 2)2 - 2(x + 3)(x - 4) = 5 - x(x - 3)
10) (x + 7)(x - 7) - (x + 2)2 = 5(x - 2) + (x - 7)
_Làm hộ với!_