Question

Tìm số đó : \(\dfrac{ 4^5 . 9^4 + 2 . 6^9 } { 2^10 . 3^8 + 6^8 . 20 }\)

Cảm ơn : )

Answer 1

\(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)

\(=\dfrac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)

\(=\dfrac{2^{10}.3^8-2^{10}.3^8.3}{2^{10}.3^8+2^{10}.3^8.5}\)

\(=\dfrac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}\)

= \(\dfrac{-2}{6}\)

= \(\dfrac{-1}{3}\)

Answer 2

\(\dfrac { 4^5 . 9^4 + 2 . 6^9 } { 2^{10} . 3^8 + 6^8 . 20 }\)