ĐKXĐ: \(x\ne0\)
\(\dfrac{x^2-2x+2007}{2007x^2}=\dfrac{2007x^2-2.2007x+2007^2}{2007^2.x^2}\)\(\Rightarrow\dfrac{\left(x-2007\right)^2}{2007^2.x^2}+\dfrac{2006}{2007^2}\ge\dfrac{2006}{2007^2}\)
Dấu " = " xảy ra \(\Leftrightarrow x=2007\)
Vậy min = \(\dfrac{2006}{2007^2}\)
cho M=((x^2-1)/(x^4-x^2+1)-1/(x^2+1))(x^4+(1-x^4)/(1+x^2)) a) rut gon b)tim min
a) Tìm min \(P=2x^2-8x+1\)
b) Tìm max \(Q=-5x^2-4x+1\)
c) Tìm min \(K=x\left(x-3\right)\left(x-4\right)\left(x-7\right)\)
d) Tìm min \(R=\dfrac{3x^2-8x+6}{x^2-2x+1}\)
tìm min B = x^2+y^2-2xy+2x-2y+5-2y^2-8y+2015
tìm min B=\(\dfrac{x^2-2x+2016}{x^2}\)
Cho x + y+ z = 2007 . Tìm min \(\dfrac{x^4}{y}+\dfrac{y^4}{z}+\dfrac{z^4}{x}\)
4(x+5)-3|2x-1|=0
\(\dfrac{2-x}{2007}-1=\dfrac{1-x}{2008}-\dfrac{x}{2009}\)
x4+4x2-5=0
Tìm min của biểu thức:
\(A=\dfrac{x^2-2x+2018}{2017x^2}\); với x khác 0
cho x+y+z=2007
tìm min \(\dfrac{x^4}{y}\)+\(\dfrac{y^4}{z}\)+\(\dfrac{z^4}{x}\)
Tìm min
\(B=\dfrac{16x^2+4x+1}{2x}\) với x>0
