Question

Tìm m, n thuộc Z sao cho 2^m - 2ⁿ = 256

Answer 1

Ta có:

\(2^m-2^n=256\)

\(\Rightarrow2^n.\left(2^{m-n}-1\right)=256\)

Do \(2^{m-n}-1\) chia 2 dư 1 mà \(256=2^8\)

\(\Rightarrow2^n=2^8;2^{m-n}-1=1\)

\(\Rightarrow n=8;2^{m-n}=2=2^1\)

\(\Rightarrow n=8;m-n=1\)

\(\Rightarrow n=8;m=9\)

Vậy \(m=9;n=8\)

Answer 2

bạn vô lik này nhé:

http://olm.vn/hoi-dap/question/164700.html

Nhớ tick cho mik