Question

tìm m để 2x³+x²-7x+m chia hết cho 2x-1 giúp mình với ạ

Answer 1

\(2x^3-x^2+2x^2-x-6x+m=x\left(2x-1\right)+x\left(2x-1\right)-3\left(2x+\dfrac{m}{3}\right)⋮2x-1\)

\(\Rightarrow\dfrac{m}{3}=-1\Leftrightarrow m=-3\)

Answer 2

\(\Leftrightarrow2x^3-x^2+2x^2-x+8x-4+m+4⋮2x-1\)

=>m+4=0

hay m=-4