Xét \(\ge\) \(\sqrt{x-4+y-3}\)
=> A \(\ge\) \(\sqrt{x+y-7}\)
Vì x + y = 15
=> A \(\ge\) \(\sqrt{15-7}\)
=> A \(\ge\) \(\sqrt{8}\)
Dấu "=" xảy ra khi: \(\left[{}\begin{matrix}x-4=0\\y-3=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=4\\y=3\end{matrix}\right.\)