\(A=x-x^2=-x^2+x=-\left(x^2-x+\dfrac{1}{4}-\dfrac{1}{4}\right)=-\left(x^2-2.x.\dfrac{1}{2}+\dfrac{1}{4}-\dfrac{1}{4}\right)=-\left(x-\dfrac{1}{2}\right)^2+\dfrac{1}{4}\le\dfrac{1}{4}\)
\(\Rightarrow Max_A=\dfrac{1}{4}\Leftrightarrow x=\dfrac{1}{2}\)