\(A=\left|x-\dfrac{3}{4}\right|\ge0\)
Dấu " = " khi \(\left|x-\dfrac{3}{4}\right|=0\Rightarrow x=\dfrac{3}{4}\)
Vậy \(MIN_A=0\) khi \(x=\dfrac{3}{4}\)
\(A=I\left|x-\dfrac{3}{4}\right|\)
\(\left|x-\dfrac{3}{4}\right|\ge0\)
\(MIN_A\Leftrightarrow MIN_{\left|x-\dfrac{3}{4}\right|}\)
\(MIN_{\left|x-\dfrac{3}{4}\right|}=0\)
\(MIN_A=I.0=0\)