a) \(6x-5=613\)
\(\Leftrightarrow6x=618\)
\(\Leftrightarrow x=103\)
b) \(74\left(x-3\right)=0\)
\(\Leftrightarrow x-3=0\Leftrightarrow x=3\)
\(a,\Rightarrow6x=613+5=618\\ \Rightarrow x=103\\ b,\Rightarrow x-3=0\Rightarrow x=3\)
a,6.x-5=613
6x =613+5=618
x =103
Vậy........
b,74.(x-3)=0
x-3 =0:74=0
x = 0+3=3
Vậy .....
Giải:
a) \(6x-5=613\) b) \(74\left(x-3\right)=0\)
\(\Rightarrow6x=613+5\) \(\Rightarrow\) \(x-3=0:74\)
\(\Rightarrow\) \(6x=618\) \(\Rightarrow x-3=0\)
\(x=618:6\) \(\Rightarrow\) \(x=0+3\)
Vậy \(x=103\) Vậy \(x=3\)
Hok tốt 
a: Ta có: 6x-5=613
nên 6x=618
hay x=103
b: Ta có: 74(x-3)=0
nên x-3=0
hay x=3
