\(\left(7x+2\right)^{-1}=3^{-2}\\ \dfrac{1}{7x+2}=\dfrac{1}{9}\\ \Leftrightarrow9\cdot1=1\cdot\left(7x+2\right)\\ \Leftrightarrow7x+2=9\\ \Leftrightarrow7x=7\\ \Leftrightarrow x=7:7\\ \Rightarrow x=1\\ Vậyx=1\)
Tìm x chứ bn nhỉ!!!!
\(\left(7x+2\right)^{-1}=3^{-2}\)
\(\Rightarrow\dfrac{1}{7x+2}=\dfrac{1}{3^2}\)
\(\Rightarrow\dfrac{1}{7x+2}=\dfrac{1}{9}\)
\(\Rightarrow7x+2=9\)
\(\Rightarrow x=\left(9-2\right):7=1\)
Vậy x = 1