Question

Thực hiện phép tính :

         a) A =  2 +  \(\frac{1}{1+\frac{1}{2}}\)                                       b) B = 2 + \(\frac{1}{1+\frac{1}{2+\frac{1}{1+\frac{1}{2}}}}\)

 

Answer 1

\(2+\frac{1}{2+\frac{1}{2}}=2+\frac{1}{\frac{5}{2}}=2+\frac{5}{2}=\frac{9}{2}\)

 

Answer 2

a) \(A=2+\frac{1}{1+\frac{1}{2}}=2+\frac{1}{\frac{3}{2}}=2+\frac{2}{3}=\frac{8}{3}\)

b) \(B=2+\frac{1}{1+\frac{1}{2+\frac{1}{1+\frac{1}{2}}}}\)

Theo câu a ta được \(B=2+\frac{1}{1+\frac{1}{\frac{8}{3}}}=2+\frac{1}{1+\frac{3}{8}}=2+\frac{1}{\frac{11}{8}}=2+\frac{8}{11}=\frac{30}{11}\)

Answer 3

a) Ta có: A = \(2+\frac{1}{3}=2+\frac{2}{3}=\frac{8}{3}\)

               A = \(\frac{8}{3}\)

b) Từ kết quả câu a) ta có:

           B =     \(2+\frac{1}{1+\frac{1}{\frac{8}{3}}}=2+\frac{1}{\frac{11}{8}}=2+\frac{8}{11}=\frac{30}{11}\)

           B = \(\frac{30}{11}\)

Answer 4

bài a=\(\frac{8}{3}\)bài b=\(\frac{30}{11}\)