Câu hỏi của Dương Dương Yang Yang

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9. (1/3)3 : [(-2/3)2 + 0,5 - 1và1/2]

Nguyễn Thanh Hằng · Accepted Answer

$9\left(\dfrac{1}{3}\right)^3:\left[\left(\dfrac{-2}{3}\right)^2+0,5-1\dfrac{1}{2}\right]$

$=9.\dfrac{1}{27}:\left[\dfrac{2}{3}+0,5-1,5\right]$

$=\dfrac{1}{3}:\left[\dfrac{2}{3}+-1\right]$

$=\dfrac{1}{3}:\dfrac{-1}{3}=\dfrac{-1}{9}$Câu trả lời: $9\left(\dfrac{1}{3}\right)^3:\left[\left(\dfrac{-2}{3}\right)^2+0,5-1\dfrac{1}{2}\right]$

$=9.\dfrac{1}{27}:\left[\dfrac{2}{3}+0,5-1,5\right]$

$=\dfrac{1}{3}:\left[\dfrac{2}{3}+-1\right]$

$=\dfrac{1}{3}:\dfrac{-1}{3}=\dfrac{-1}{9}$

Linh Nguyễn · Answer

$A=9\left(\dfrac{1}{3}\right)^3:\left[\left(-\dfrac{2}{3}\right)^2+0,5-1\dfrac{1}{2}\right]$

$A=9.\dfrac{1}{3}:\left(\dfrac{4}{9}+\dfrac{1}{2}-\dfrac{3}{2}\right)$

$A=3:\left(\dfrac{8}{18}+\dfrac{9}{18}-\dfrac{27}{18}\right)$

$A=3:-\dfrac{5}{9}$

$A=-\dfrac{27}{5}$Câu trả lời: $A=9\left(\dfrac{1}{3}\right)^3:\left[\left(-\dfrac{2}{3}\right)^2+0,5-1\dfrac{1}{2}\right]$

$A=9.\dfrac{1}{3}:\left(\dfrac{4}{9}+\dfrac{1}{2}-\dfrac{3}{2}\right)$

$A=3:\left(\dfrac{8}{18}+\dfrac{9}{18}-\dfrac{27}{18}\right)$

$A=3:-\dfrac{5}{9}$

$A=-\dfrac{27}{5}$

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