A=(2x+3)(x^2-x+2) - 2x(x^2+1/2x-3)
=(2x^3- 2x^2+4x+3x^2-3x+6) - (2x^3+x^2-6x)
=2x^3 - 2x^2 + 4x + 3x^2 - 3x + 6 - 2x^3 - x^2 - 6x
=6 - 5x
ta có : (x+2)^2 + (x-3)^2 - 2(x-3)(x+2)=4x+13
<=> [(x+2) -(x-3)]^2=4x+13
<=>(x+2-x+3)=4x+13
<=>4x+13=5
=>4x= 5-13=-8
=>x=-8/4=-2