ĐKXĐ: ...
Ta có: \(\sqrt{\frac{2x-3}{x-1}}=2\)
\(\Leftrightarrow\frac{2x-3}{x-1}=4\)
\(\Leftrightarrow2x-3=4\left(x-1\right)\)
\(\Leftrightarrow2x-3=4x-4\)
\(\Leftrightarrow2x-3-4x+4=0\)
\(\Leftrightarrow-2x+1=0\)
\(\Leftrightarrow-2x=-1\)
hay \(x=\frac{1}{2}\)(thỏa mãn)
Vậy: \(S=\left\{\frac{1}{2}\right\}\)