`\sqrt{4x-3}-\sqrt{x^2-3}=0` `ĐK: x >= \sqrt{3}`
`<=>\sqrt{4x-3}=\sqrt{x^2-3}`
`<=>4x-3=x^2-3`
`<=>x^2-4x=0`
`<=>x(x-4)=0`
`<=>[(x=0(ko t//m)),(x=4(t//m)):}`
Vậy `S={4}`.
\(\sqrt{x^2+4x+6}\) \(\Leftrightarrow x^2+4x+6=0\)
Tới đây mình bí quá, mọi người giúp mình với ạ
Cần gấp lắm ạ!
giải pt sau
1, \(\sqrt{5-2x}=6\)
2,\(\sqrt{2-x}-\sqrt{x+1}=0\)
3, \(\sqrt{4x^2+4x+1}=6\)
4,\(\sqrt{x^2-10x+25}=x-2\)
Gpt :
1) \(\sqrt{x-1}+\sqrt{4x-4}-\sqrt{25x-25}+2=0\)
2) \(\sqrt{16x+16}-\sqrt{9x+9}+\sqrt{4x+s}+\sqrt{x+1}=16\)
3)\(\sqrt{4x+20}+\sqrt{x+5}-\frac{1}{3}\sqrt{9x+45}=4\)
4) \(\frac{1}{3}\sqrt{2x}-\sqrt{8x}+\sqrt{18x}-10=2\)
Giải phương trình :
a)\(\sqrt{2x-3}=\sqrt{x-1}\)
b) \(\sqrt{36x-36}-\sqrt{9x-9}-\sqrt{4x-4}=16-\sqrt{x-1}\)
c)\(\sqrt{2x+3}+\sqrt{2x+2}=1\)
d)\(\sqrt{4x^2+4x+1}=3\)
Giúp mình với ạ ! Mai mình nộp ròi !!!
Giải các phương tình sau:
a) \(x^3-3x^2+12x-5=2\sqrt{5x-1}+\sqrt[3]{3x-2}\)
b) \(4x^2+24x+17=2\sqrt{2x+5}+\sqrt[3]{4x+10}\)
c) \(2x^3-5x^2+16x-3=2\sqrt[3]{4x-1}+\sqrt[3]{2x+7}\)
d) \(2x^2+11x+12=2\sqrt{2x+3}+\sqrt[3]{x+2}\)
e) \(2x^2+3x-3-2\sqrt{2x+1}-\sqrt[3]{4x+2}=0\)
Cho A=(\(\left(\dfrac{2-\sqrt[3]{4x}}{x-\sqrt[3]{2x^2}}\right):\left(\sqrt[3]{2}+\sqrt[3]{x}\right)-\dfrac{1}{\sqrt[3]{x}}\) với x≠0;-2. Tìm x nguyên sao cho A3 nguyên
\(\sqrt{4x-12}+\sqrt{9x-27}-4\sqrt{x-3}+3-x=0\)
(\(5\sqrt{x}-1\)) (\(\sqrt{x}-2\)) - (2\(\sqrt{x}\) - 1)2 = 1
<=> ( 5x - 10\(\sqrt{x}\) - \(\sqrt{x}\)+ 2 ) - ( 4x - \(4\sqrt{x}\)+ 1 ) = 1
<=> 5x - 10\(\sqrt{x}\) - \(\sqrt{x}\)+ 2 - 4x + \(4\sqrt{x}\)+ 1 -1 = 0
<=> x -7\(\sqrt{x}\) + 2= 0
xong rồi làm thế nào nữa ạ ?
giải phương trình
a)\(\sqrt{2x}-\sqrt{98}=0\)
b)\(\sqrt{2x}=\sqrt{8}\)
c)\(\sqrt{5x^2}=\sqrt{20}\)
d)\(\sqrt{2x}-3\sqrt{8x}+4\sqrt{32x}=52\)
e)\(3\sqrt{x-1}+2\sqrt{4x-4}-3\sqrt{9x-9}=-6\)
f)\(\sqrt{x-1}+\sqrt{4x-4}-\sqrt{25x-25}+2=0\)
g)\(\sqrt{9x^2+18}+2\sqrt{x^2+2}-\sqrt{25x^2+50+3}=0\)
h)\(\sqrt{x-1}=\sqrt{3}\)
k)\(\sqrt{9x^2-6x+1}=3\)
l)\(\sqrt{2x-1}=2\)
m)\(\sqrt{x+2}=\sqrt{3-x}\)
n)\(\sqrt{4x^2}-4x+1=\sqrt{7-4\sqrt{3}}+\sqrt{7+4\sqrt{3}}\)
