\(\sqrt{29-12\sqrt{5}}=\sqrt{20-12\sqrt{5}+9}=\sqrt{\left(2\sqrt{5}-3\right)^2}=2\sqrt{5}-3\)
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Bài 1: Căn bậc hai
Các câu hỏi tương tự
rút gọn các biểu thức sau:
a,\(\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}}\)
b,\(\sqrt{6+2\sqrt{5}-\sqrt{29-12\sqrt{5}}}\)
c,\(\sqrt{2+\sqrt{5-\sqrt{13-\sqrt{48}}}}\)
d,\(\left(3-\sqrt{5}\right)\sqrt{3+\sqrt{5}}+\left(3+\sqrt{5}\right)\sqrt{3-\sqrt{5}}\)
1,\(\sqrt{49-12\sqrt{ }5}+\sqrt{49+12\sqrt{ }5}\)
2,\(\sqrt{29+12\sqrt{ }5}\)+\(\sqrt{29-12\sqrt{ }5}\)
3,\(\sqrt{31-12\sqrt{ }3}-\sqrt{31+12\sqrt{ }3}\)
4,\(\sqrt{39-12\sqrt{ }3}-\sqrt{39+12\sqrt{ }3}\)
tính :
\(\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}}\)
\(\sqrt{29-12\sqrt{5}}\)
\(\sqrt{29-12\sqrt{5}}\)
Câu a :
\(\sqrt{4+\sqrt{5\sqrt{3}+5\sqrt{48-10\sqrt{7+4\sqrt{3}}}}}\)
Câu b:
\(\sqrt{\sqrt{5-\sqrt{3-\sqrt{29-12\sqrt{5}}}}}\)
Tính \(C=\sqrt{13+30\sqrt{2+\sqrt{9+4\sqrt{2}}}}\)
Tính\(D=\sqrt{6+2\sqrt{5-\sqrt{29-12\sqrt{5}}}}\)
Rút gọn biểu thức
a. \(A=\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-\sqrt{12\sqrt{5}}}}}\)
b. \(B=\left(4+\sqrt{15}\right)\left(\sqrt{10}-\sqrt{6}\right)\left(\sqrt{4-\sqrt{15}}\right)\)
Bài 1: Tính
a sqrt{6+2sqrt{5}} + sqrt{6-2sqrt{5}}
b sqrt{5+2sqrt{6}} + sqrt{5-2sqrt{6}}
c sqrt{8-2sqrt{7}} - sqrt{8+2sqrt{7}}
d sqrt{29+12sqrt{5}} + sqrt{29-12sqrt{5}}
e ( sqrt{0,25} - sqrt{225} + sqrt{2,25}) : sqrt{169}
f 3 - sqrt{5} + 3 + sqrt{5}
Đọc tiếp
Bài 1: Tính
a> \(\sqrt{6+2\sqrt{5}}\) + \(\sqrt{6-2\sqrt{5}}\)
b> \(\sqrt{5+2\sqrt{6}}\) + \(\sqrt{5-2\sqrt{6}}\)
c> \(\sqrt{8-2\sqrt{7}}\) - \(\sqrt{8+2\sqrt{7}}\)
d> \(\sqrt{29+12\sqrt{5}}\) + \(\sqrt{29-12\sqrt{5}}\)
e> ( \(\sqrt{0,25}\) - \(\sqrt{225}\) + \(\sqrt{2,25}\)) : \(\sqrt{169}\)
f> 3 - \(\sqrt{5}\) + 3 + \(\sqrt{5}\)