Phần a sai đề sửa đề
\(A=\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-{12\sqrt{5}}}}}\)
=\(\sqrt{\sqrt{5}-\sqrt{3-\sqrt{(2\sqrt{5}-3)^2 } } } \)
=\(\sqrt{5-\sqrt{3-2\sqrt{5}+3 }}\)
=\(\sqrt{\sqrt{5}-\sqrt{(\sqrt{5}-1)^2 } } \)
=\(\sqrt{\sqrt{5}-\sqrt{5}+1 } \)
=1
B=\((\sqrt{4+\sqrt{15} }) \sqrt{2}(\sqrt{5}-\sqrt{3})(\sqrt{4-\sqrt{15} })({\sqrt{4+\sqrt{15} }) } \)
=(\((\sqrt{4+\sqrt{15} })\sqrt{2}(\sqrt{5}-\sqrt{3}) \)
=\((\sqrt{8+2\sqrt{15} })(\sqrt{5}-\sqrt{3}) \)
=\((\sqrt{5}+\sqrt{3})(\sqrt{5}-\sqrt{3}) \)
=2