Đề đúng theo như bn sửa: So sánh: \(\sqrt{2}+\sqrt{11}\)và\(\sqrt{3}+5\)
Ta có: \(\sqrt{2}+\sqrt{11}< \sqrt{4}+\sqrt{16}=2+4=6\)
\(\sqrt{3}+5>\sqrt{1}+5=1+5=6\)
=> \(\sqrt{2}+\sqrt{11}< \sqrt{3}+5\)
\(\sqrt{2}\) + \(\sqrt{11}\) và \(\sqrt{3}\) + 5
Ta có: \(\sqrt{3}\) + 5 = \(\sqrt{3}\) + \(\sqrt{25}\)
Ta thấy: 2 + 11 < 3 +25 hay \(\sqrt{2}\) + \(\sqrt{11}\) < \(\sqrt{3}\) + \(\sqrt{25}\)
\(\Rightarrow\) \(\sqrt{2}\) + \(\sqrt{11}\) < \(\sqrt{3}\) + 5