d)
Ta có: \(\dfrac{1}{51}>\dfrac{1}{100}\)
\(\dfrac{1}{52}>\dfrac{1}{100}\)
...
\(\dfrac{1}{99}>\dfrac{1}{100}\)
\(\dfrac{1}{100}=\dfrac{1}{100}\)
\(\Rightarrow S=\dfrac{1}{51}+\dfrac{1}{52}+...+\dfrac{1}{99}+\dfrac{1}{100}>\dfrac{1}{100}.50=\dfrac{1}{2}\)\(\Rightarrow S>\dfrac{1}{2}\)
câu b
có
\(\dfrac{183}{184}< 1\)
và
\(\dfrac{-184}{-183}=\dfrac{184}{183}>1\)
=> \(\dfrac{183}{184}< \dfrac{-184}{-183}\)
câu c
có
\(\dfrac{29}{40}>\dfrac{29}{41}\)
và
\(\dfrac{29}{41}>\dfrac{28}{41}\)
\(=>\dfrac{29}{40}>\dfrac{29}{41}>\dfrac{28}{41}\)
câu a vì dài quá nên mình lười