Đặt A = \(2\sqrt{3}\), B = \(3\sqrt{2}\). Ta có:
A = \(2\sqrt{3}\)
\(\Rightarrow\) A2 = (\(2\sqrt{3}\))2 = 4 . 3 = 12
B = \(3\sqrt{2}\)
\(\Rightarrow\) B2 = (\(3\sqrt{2}\))2 = 9 . 2 = 18
VÌ 18 > 12 nên A < B hay \(2\sqrt{3}\) < \(3\sqrt{2}\)
Vậy...
Ta có \(2\sqrt{3}=\sqrt{2^2.3}=\sqrt{4.3}=\sqrt{12}\)
\(3\sqrt{2}=\sqrt{3^2.2}=\sqrt{9.2}=\sqrt{18}\)
Vì \(18>12\Leftrightarrow\sqrt{18}>\sqrt{12}\Leftrightarrow3\sqrt{2}>2\sqrt{3}\)
Vậy \(2\sqrt{3}< 3\sqrt{2}\)