Question

Rút gọn rồi tính giá trị biểu thức :

A= (x+1).(\(x^2\)-x+1) +x-(x-1).(\(x^2\)+x+1)+2021

Tại x= -2022

 

Answer 1

\(A=\left(x+1\right)\left(x^2-x+1\right)+x-\left(x-1\right)\left(x^2+x+1\right)+2021\)

\(=x^3+1+x-x^3+1+2021\)

\(=x+2023\)

=-2022+2023

=1

Answer 2

\(A=\left(x+1\right)\left(x^2-x+1\right)+x-\left(x-1\right)\left(x^2+x+1\right)+2021=x^3+1+x-x^2+1+2021=x+2023=-2022+2023=1\)