Question

Rút gọn biểu thức:

\(\left(x+1\right)^2+\left(2x+2\right)\left(2x-3\right)-\left(3-2x\right)^2\)

Answer 1

\(\left(x+1\right)^2+\left(2x+2\right)\left(2x-3\right)-\left(3-2x\right)^2\)

\(=\left(x+1\right)^2+\left(2x+2\right)\left(2x-3\right)-\left(2x-3\right)^2\)

\(=\left(2x-3\right)\left(2x+2-2x+3\right)+\left(x^2+2x+1\right)\)

\(=5\left(2x-3\right)+x^2+2x+1\)

\(=x^2+12x-14\)

Answer 2

`= x^2 + 2x + 1 + 4x^2 - 2x - 6 - 9 + 12x - 4x^2`

`= x^2 + 12x - 14`

Answer 3

\(\left(x+1\right)^2+\left(2x+2\right)\left(2x-3\right)-\left(3-2x\right)^2\)

\(=x^2+2x+1+4x^2-6x+4x-6-9+6x-4x^2\)

\(=x^2+6x-14\)