ĐKXĐ : \(x\sqrt{x}+3\sqrt{3}\ne0\)
=> \(x\ne-3\)
- Ta có : \(\frac{x-3\sqrt{x}+3}{x\sqrt{x}+3\sqrt{3}}\)
\(=\frac{x-3\sqrt{x}+3}{\sqrt{x}^3-\sqrt{3}^3}\)\(=\frac{x-3\sqrt{x}+3}{\left(\sqrt{x}-\sqrt{3}\right)\left(x-3\sqrt{x}+3\right)}=\frac{1}{\sqrt{x}-\sqrt{3}}\)