Question

Rút gọn biểu thức: B=\(\dfrac{\sqrt{x}+1}{x-1}-\dfrac{x-2\sqrt{x}-3}{x-1}\)

Answer 1

\(B=\dfrac{\sqrt{x}+1-x+2\sqrt{x}+3}{x-1}\)

\(=\dfrac{-x+4\sqrt{x}+4}{x-1}\)

Answer 2

đk x ≠1

\(B=\dfrac{\sqrt{x}+1-x+2\sqrt{x}+3}{x-1}=\dfrac{-x+3\sqrt{x}+4}{x-1}=\dfrac{-x+4\sqrt{x}-\sqrt{x}+4}{x-1}=\dfrac{-\sqrt{x}\left(\sqrt{x}-4\right)-\left(\sqrt{x}-4\right)}{x-1}=\dfrac{-\left(\sqrt{x}+1\right)\left(\sqrt{x}-4\right)}{x-1}=\dfrac{-\left(\sqrt{x}-4\right)}{\sqrt{x}-1}\)