Question

Rút gọn :A=\(\dfrac{a^2+\sqrt{a}}{a-\sqrt{a}+1}\)-\(\dfrac{2a+\sqrt{a}}{\sqrt{a}}\)+1

Giúp mik luôn vs ạ

Mik đg cần gấp.Thank you

Answer 1

\(A=\dfrac{a^2+\sqrt{a}}{a-\sqrt{a}+1}-\dfrac{2a+\sqrt{a}}{\sqrt{a}}+1\)

\(=a+\sqrt{a}-2\sqrt{a}-1+1\)

\(=a-\sqrt{a}\)

Answer 2

A=\(\dfrac{\sqrt{a}\left(\sqrt{a^3}+1\right)}{a-\sqrt{a}+1}-\dfrac{\sqrt{a}\left(2\sqrt{a}+1\right)}{\sqrt{a}}+1\)

A=\(\dfrac{\sqrt{a}\left(\sqrt{a}+1\right)\left(a-\sqrt{a}+1\right)}{a-\sqrt{a}+1}-\left(2\sqrt{a}+1\right)+1\)

A=\(a+\sqrt{a}-2\sqrt{a}-2+1=a-\sqrt{a}-1\)