\(=\dfrac{2^{19}\cdot3^9+3\cdot5\cdot2^{18}\cdot3^8}{3^9\cdot2^9\cdot2^{10}\cdot2^{20}\cdot3^{10}}=\dfrac{2^{18}\cdot3^9\cdot\left(2+5\right)}{3^{19}\cdot2^{39}}\)
\(=\dfrac{7}{3^{10}\cdot2^{21}}\)
Rút gọn
a)\(\frac{25^{5^{ }}.5^{10}}{100^5}.\frac{4^6.9^5+6^9.120}{8^4.3^{12^{ }}-6^{11}}\)
b)\(\left(\frac{4}{9}+\frac{1}{3}\right)^2+\left(\frac{3}{4}\right)^2:\left(\frac{3}{4}\right)^2:\left(-\frac{2}{3}\right)^3\)
c) (273 : 33) : \(\left[\left(\frac{3}{5}\right)^{15}:\left(\frac{9}{25}\right)^5\right]\)
CÁC BẠN GIÚP MIH VỚI
Tính:
a,A=\(\dfrac{12^{15}.3^4-4^5.3^9}{27^3.2^{10}-32^3.3^9}\)
b. B= \(\dfrac{3}{1^2.2^2}+\dfrac{5}{2^3.3^2}+\dfrac{7}{3^2.4^2}+...+\dfrac{99}{49^2.50^2}\)
1/ So sánh: \(\dfrac{4^{1008}}{5^{2015}}\) và \(\dfrac{16^{504}.3^{2016}}{5^{2016}.4^{1008}}\)
2/ Rút gọn:
a/ \(\dfrac{2^{12}.27^3+4^5.9^6}{8^3.3^{10}+6^{10}}\)
b/ \(\dfrac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}}\)
c/ \(\dfrac{4^{10}+8^4}{4^5+8^6}\)
3/ Biết: \(2^2+3^2+4^2+...+13^2=816\)
Tính: \(B=1^2+3^2+6^2+9^2+...+39^2\)
4/ Chứng tỏ:
a/ \(3^{15}-9^6⋮13\)
b/ \(8^7-2^{18}⋮14\)
5/ Tìm GTLN của biểu thức:
\(A=x^2+3\left|y-2\right|+1\)
6/ Tìm GTNN của biểu thức:
\(B=\left(-5\right)-\left(2x-1\right)^2\)
thưc hiện phép tính:
H = \(\dfrac{2^{19}.27^3.5-15.\left(-4\right)^9.9^4}{6^9.2^{10}-\left(-12\right)^{10}}\)
Tính giá trị biểu thức :
\(H=\frac{2^{19}.27^3.5-15.\left(-4\right)^9.9^4}{6^9.2^{10}-\left(-12\right)^{10}}\)
Bài 1: Rút gọn:
a) \(\dfrac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)
b) \(\dfrac{\left(\dfrac{-1}{2}\right)^3-\left(\dfrac{3}{4}\right)^3.\left(-2\right)^2}{2.\left(-1\right)^5+\left(\dfrac{3}{4}\right)^2-\dfrac{3}{8}}\)
* Giúp mình với... mình đang cần gấp................
Rút gọn
B = \(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
thưc hiện phép tính:
H = \(\dfrac{2^{19}.27^3.5-15.\left(-4\right)^9.9^7}{6^9.2^{10}-\left(-12\right)^{10}}\)
\(\dfrac{\left(13\dfrac{1}{4}-2\dfrac{5}{27}-10\dfrac{5}{6}\right).230\dfrac{1}{25}+46\dfrac{3}{4}}{\left(1\dfrac{3}{10}+\dfrac{10}{3}\right):\left(12\dfrac{1}{3}-14\dfrac{2}{7}\right)}\)
\(\dfrac{\left(1+2+3+...+99+100\right)\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{7}-\dfrac{1}{9}\right)\left(63.1,2-21.3,6\right)}{1-2+3-4+.....+99-100}\)
