Question

quy đồng mẫu thức phân thức 4/x^2-3x+2 và 1/x^2-x

Answer 1

\(\dfrac{4}{x^2-3x+2}\)   và   \(\dfrac{1}{x^2-x}\)

\(\dfrac{4}{x^2-3x+2}=\dfrac{4}{\left(x-1\right)\left(x-2\right)}\)

\(\dfrac{1}{x^2-x}=\dfrac{1}{x\left(x-1\right)}\)

`MSC: x(x-1)(x-2)`

\(\dfrac{4}{\left(x-1\right)\left(x-2\right)}=\dfrac{4\cdot x}{x\left(x-1\right)\left(x-2\right)}=\dfrac{4x}{x\left(x-1\right)\left(x-2\right)}\)

\(\dfrac{1}{x\left(x-1\right)}=\dfrac{1\cdot\left(x-2\right)}{x\left(x-1\right)\left(x-2\right)}=\dfrac{x-2}{x\left(x-1\right)\left(x-2\right)}\)