Question

Phân tích đa thức thành nhân tử: x^5-x

Answer 1

\(x^5-x\\ =x\left(x^4-1\right)\\ =x\left(x^2-1\right)\left(x^2+1\right)\\ =x\left(x-1\right)\left(x+1\right)\left(x^2+1\right)\)

Answer 2

Ta có: \(x^5-x\)

\(=x\left(x^4-1\right)\)

\(=x\left(x^2-1\right)\left(x^2+1\right)\)

\(=x\left(x-1\right)\left(x+1\right)\left(x^2+1\right)\)