PTHH : \(2Al+3CuCl_2-->2AlCl_3+3Cu\)
Đặt \(n_{Al\left(pứ\right)}=x\left(mol\right)\)
Theo PTHH : \(n_{Cu}=\dfrac{3}{2}n_{Al}=\dfrac{3}{2}x\left(mol\right)\)
=> \(\dfrac{3}{2}x\cdot64-27x=2,07\)
=> \(x=0,03\left(mol\right)\)
=> \(m_{Cu}=\dfrac{3}{2}\cdot x\cdot64=2,88\left(g\right)\)