Question

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Answer 1

d) \(24^4:3^4-32^{12}:16^{12}\)

\(=\left(24:3\right)^4-\left(32:16\right)^{12}\)

\(=8^4-2^{12}\)

\(=\left(2^3\right)^4-2^{12}\)

\(=2^{12}-2^{12}\)

\(=0\)

Answer 2

h: \(\dfrac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}=\dfrac{11\cdot3^{29}-3^{30}}{4\cdot3^{28}}=\dfrac{3^{29}\cdot8}{4\cdot3^{28}}=3\cdot2=6\)