\(c,\Leftrightarrow3x-5-x-7=2\Leftrightarrow2x-12=2\Leftrightarrow2x=14\Leftrightarrow x=7\)
\(d,\left\{{}\begin{matrix}x=6\\y-1=6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=6\\y=7\end{matrix}\right.\)
Câu C:
(3x−5)−(x+7)=2
3x−5−x−7=2
2x−5−7=2
2x−12=2
2x=2+12
2x=14
x=214
x=7