Question

Log₃₆2 - 1/2log_1/63

Answer 1

\(\log_{6^2}2-\frac{1}{2}\log_{\frac{1}{6}}3=\frac{1}{2}\log_62+\frac{1}{2}\log_63=\frac{1}{2}\log_6\left(2.3\right)=\frac{1}{2}\log_66=\frac{1}{2}\)

Answer 2

Tại sao log_6²2 - 1/2log_1/63 lại <=> 1/2log₆2 + 1/2 log_{63 ạ?}

Answer 3

đấy là công thứ tính nhé

\(\log_{a^{\alpha}}b=\frac{1}{\alpha}\log_ab\)

Answer 4

\(\log_{\frac{1}{6}}3=\log_{6^{-1}}3=\frac{1}{-1}\log_63=-\log_63\)