\(C_6H_{12}O_6⇌\left(men.rượu,30-35^oC\right)2C_2H_5OH+2CO_2\\ CO_2+Ca\left(OH\right)_2\rightarrow CaCO_3+H_2O\\ n_{CO_2}=n_{Ca\left(OH\right)_2}=\dfrac{15}{100}=0,15\left(mol\right)\\ n_{C_6H_{12}O_6\left(LT\right)}=\dfrac{0,15}{2}=0,075\left(mol\right)\\ m=m_{C_6H_{12}O_6\left(TT\right)}=0,075.180=13,5\left(g\right)\)