\(\left(x^2+1\right).\left(x^3+27\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x^2+1=0\\x^3+27=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x^2=0-1\\x^3=0-27\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x^2=-1\\x^3=-27\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x\in\varnothing\\x=-3\end{matrix}\right.\)
Vậy \(x=-3.\)
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