Question

\(\left(\dfrac{2}{3}-\dfrac{1}{4}+\dfrac{5}{11}\right):\left(\dfrac{5}{12}+1-\dfrac{7}{11}\right)\)

Answer 1

\(=\left(\dfrac{2.44-33+5.12}{132}\right):\left(\dfrac{5.11+132-7.12}{132}\right)=\left(\dfrac{88-33+60}{132}\right):\left(\dfrac{55+132-84}{132}\right)=\dfrac{115}{132}:\dfrac{103}{132}=\dfrac{115}{132}.\dfrac{132}{103}=\dfrac{115}{103}\)

Answer 2

`(2/3 - 1/4 + 5/11) : (5/12 + 1 - 7/11)`

`= 115/132 : 103/132`

`= 115/103`.

Answer 3

=\(\left(\dfrac{5}{12}+\dfrac{5}{11}\right):\left(\dfrac{17}{12}-\dfrac{17}{11}\right)\) 

=\(\dfrac{115}{132}:\left(-\dfrac{17}{132}\right)=\dfrac{115}{132}\times\left(-\dfrac{132}{17}\right)\) 

\(=-\dfrac{115}{17}\)

Answer 4

\(=\)\(\left(\dfrac{5}{12}+\dfrac{5}{11}\right):\left(\dfrac{5}{12}+1-\dfrac{7}{11}\right)\)

\(=\)\(\dfrac{115}{132}:\left(\dfrac{17}{12}-\dfrac{7}{11}\right)\)

\(=\dfrac{115}{132}:\dfrac{103}{132}\)

\(=\dfrac{115}{132}.\dfrac{132}{103}=\dfrac{115}{103}\)