Question

\(\left(\dfrac{1}{2}\right)^{2n-1}=\dfrac{1}{8}\)

Mn giải hộ em ak

Answer 1

Ta có: \(\left(\dfrac{1}{2}\right)^{2n-1}=\dfrac{1}{8}\)

\(\Leftrightarrow2n-1=3\)

\(\Leftrightarrow2n=4\)

hay n=2

Answer 2

\(\left(\dfrac{1}{2}\right)^{2n-1}=\dfrac{1}{8}\)

\(\Rightarrow\left(\dfrac{1}{2}\right)^{2n-1}=\left(\dfrac{1}{2}\right)^3\)

\(\Rightarrow2n-1=3\)

\(\Rightarrow n=2\)