\(\Leftrightarrow\left\{{}\begin{matrix}y^2+y-2=0\\x^2-3x-4=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}\left[{}\begin{matrix}y=1\\y=-2\end{matrix}\right.\\\left[{}\begin{matrix}x=-1\\x=4\end{matrix}\right.\end{matrix}\right.\)
Vậy hệ đã cho có 4 cặp nghiệm:
\(\left(x;y\right)=\left(-1;1\right);\left(-1;-2\right);\left(4;1\right);\left(4;-2\right)\)