a) Gọi nCO2 = a (mol); nSO2 = b (mol)
mT = 44a + 64b (g)
mCO2 = 44a = (44a + 64b).40%
<=> 26,4a=25,6b
<=> 1,03125a=b
\(nCO2=\frac{a}{a+b}.100\%=\frac{a}{a+1,03125a}.100\%=49,23\%\)
nSO2 = 100% - 49,23% = 50,77%
b) \(M_T=\frac{44a+64b}{a+b}=\frac{44a+64.1,03125a}{a+1,03125a}=\frac{110}{2,03125}\approx54\)