$$\begin{array}{rcl}
\dfrac1{2000 \cdot 1999} - P &=& \dfrac1{1\cdot 2} + \dfrac1{2\cdot 3} + \ldots + \dfrac1{1998 \cdot 1999} \\
&=& \dfrac11 - \dfrac12 + \dfrac12 - \dfrac13 + \ldots + \dfrac1{1998} - \dfrac1{1999} \\
&=& 1 - \dfrac1{1999} \\
\implies P &=& \dfrac1{2000 \cdot 1999} - \left( 1 - \dfrac1{1999} \right) = -\dfrac{3995999}{3998000} \\
\end{array}$$
Nguyễn Huy Thắng
Nguyễn Huy Tú
soyeon_Tiểubàng giải
\(-\frac{1}{1998001}\) là sai rùi bạn